if you want a candy:

I need integration of
Sqrt(ax - x^3) dx
Send me your address for candy. For the first correct replier only!
(This is not a legal binding contract)

1/2 (ax-x^3 )^(-1/2) a (-3 x^2)

= -3a/2 (ax-x^3 )^(-1/2)

here is the answer:
Eat that candy by yourself

Oops! owe,wot i did was differentiation...

Hyperthread dude, a sincere thanks.

the online "webmathematica Integrator" is amazing! You can still have your candy- just send me your home address to kathmanducity@mailcity.com; if you decline, "shwetaa" can claim it.

Hehe..ho ni? :d

candy chahi hoina yo rajesh hamal lai afnu homework naako thiyo timiharu le solve gari diyau.

Hoina Bidhan,

I had to do some engineering calculations of water discharge over a weir with semi-circular opening. Homework nai ta hoina, but headache nevertheless.

Timlai candy chahincha vannee email me. Nobody else has claimed it yet.

kura chahi thul thulo garne ani jabo sajilo differentiation naako.

Hare rajesh bro , dont take it otherwise, but as being an engineer/engineering student? you dont know how to solve them , dont even know how to search online to solve them ...
damn!!!!!!!!!!!!!!!!!!

dont take it seriously though !!

ke garne?

Padne belama guccha kheldai furshad vayena!

But integration is never "sajilo" hai.

hahahah differnetition lai integration re.

ho yo pakka guchchaa khelne engineer ho.

Rajesh bro I will be scared to use anything related to your design , hehehee
By the way are you an Electrical Engineer(hydro-power)?

Clarification:

1. Bidhan dude, the initial question of mine was to find Integration. Kosle "differentition lai integration.." vanera lyayo? Kya bekaar ko kuro garcha! Jaam gucchaa khelna- you and me.

2. Yeah, hyper dude, thanks. Afterall, I did online search, didn't I? Oh, is sajha forum not considered "online" then? (By the way, I did do many online searches/research before resorting to sajha) And I do owe you a candy.

Rajesh Bro thikai chha we will take candy later ! Have fun solving your problems.

Yea,was supposed to integrate it..sorry differentiation garidiyo,by mistake !
No probs,now u have both :)

Hmm..interesting to see mathematicians at Sajha.
Here is a proof I want you guys to do without searching anywhere...shshsh..dont cheat...

Prove that as 0.999999 tends to infinity, it tends to infinity. It is pretty simple actually.

Prove that Sqrt of 2 is irrational. This one is a bit tricky though. Hint: Try to work the opposite way or in other words, prove that Sqrt 2 cannot be rational and if it cannot be rational, it has to be irrational.

Good luck!!!
PS: First one to give the correct answers to both will get a cash prize of $100 on April 1st.

Prove that as 0.999999 tends to infinity, it tends to infinity. It is pretty simple actually.

Correction...read that as 0.999999 tends to infinity, it equals 1. (remember it is not 0.9999... tends to 1, but rather =1)

Use MAT LAB

euthanasia,
I ain't asking a favor here. Just wanted others to try those simple proofs. And, my suggestion was to do that without any web or software help.